Web Development Questions That Don't Need Their Own Thread v2

[TeratybeS]

[url]http://stackoverflow.com/questions/6595935/problem-with-algorythm-to-shorten-sentences[/url]

[compwhizii]

[QUOTE=TeratybeS;30935719]My query looks something like this right now

SELECT id, body, upvotes, downvotes FROM suggestions WHERE id = :id

I understand what you mean, but using multiple limits won't work

[editline]6th July 2011[/editline]

Maybe I'm just doing it wrong though

[editline]6th July 2011[/editline]

SELECT id, body, upvotes, downvotes FROM suggestions WHERE id = 22 OR id < 22 OR id > 22 LIMIT 3

This doesn't work. Selects the following two, not the previous one.[/QUOTE]

You're going to need a separate query it seems

[Chuushajou]

I want to blur the left and right edges of the page, I'm using CSS3 for the blurring, and tried " -webkit-box-shadow-left: 0px 0px 15px 0px #000000; " and it was quickly apparent that I cannot use "-left" to just blur one side :rolleyes: So how will I do this? by using three separate divs, one of left another for right and one for content and a mix of overflow:hidden? Visual reference below;

[IMG][URL]http://i.imgur.com/HtuE2.png[/URL][/IMG]

I'll appreciate any help :downs:

[Richy13]

Can people use a site with AJAX without javascript enabled?

[StinkyJoe]

[QUOTE=Richy19;30945558]Can people use a site with AJAX without javascript enabled?[/QUOTE]

No. The J in AJAX stands for Javascript.

[Richy13]

[QUOTE=StinkyJoe;30945675]No. The J in AJAX stands for Javascript.[/QUOTE]

So how can you provide the ajax functionality for users that dont have js

[bbang]

[QUOTE=Richy19;30946512]So how can you provide the ajax functionality for users that dont have js[/QUOTE]

You make it so people cant access your site without javascript.

[Ac!dL3ak]

[QUOTE=Richy19;30946512]So how can you provide the ajax functionality for users that dont have js[/QUOTE]

you can't

[deadeye5362]

[QUOTE=Richy19;30946512]So how can you provide the ajax functionality for users that dont have js[/QUOTE]

You can always make some fallbacks. For example, a link that would normally trigger content to load dynamically VIA AJAX will just take you a static version of the page.

[bbang]

Uhm i wanted to make my url from

[url]http://link.com/blah?p=VARIABLE[/url] to [url]http://link.com/VARIABLE[/url]

and right now i have

RewriteRule ^$ coolstuffbrah.php [L]
RewriteRule ^(.*)$ coolstuffbrah.php?p=$1 [L]

just doesn't work.

[StinkyJoe]

[QUOTE=zzlawlzz;30952503]Uhm i wanted to make my url from

[URL]http://link.com/blah?p=VARIABLE[/URL] to [URL]http://link.com/VARIABLE[/URL]

and right now i have

RewriteRule ^$ coolstuffbrah.php [L]
RewriteRule ^(.*)$ coolstuffbrah.php?p=$1 [L]

just doesn't work.[/QUOTE]

RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-f
RewriteRule ^(.*)$ index.php [QSA,L]

Be sure to enable mod_rewrite in your httpd.con file.

[bbang]

[QUOTE=StinkyJoe;30952565]

RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-f
RewriteRule ^(.*)$ index.php [QSA,L]

Be sure to enable mod_rewrite in your httpd.con file.[/QUOTE]

Ya, the rewrite isn't a problem.

when I add a 'page' it works fine

RewriteRule ^$ coolstuffbrah.php [L]
RewriteRule ^page$ coolstuffbrah.php [L]
RewriteRule ^page/(.*)$ coolstuffbrah.php?p=$1 [L]

but I dont want an extra page, I just want it to be like url.com/VARIABLE

[StinkyJoe]

With my method you use $_SERVER['REQUEST_URI'] to get the original request uri, you have to work with that.

[TheDecryptor]

[QUOTE=Chuushajou;30945486]I want to blur the left and right edges of the page, I'm using CSS3 for the blurring, and tried " -webkit-box-shadow-left: 0px 0px 15px 0px #000000; " and it was quickly apparent that I cannot use "-left" to just blur one side :rolleyes: So how will I do this? by using three separate divs, one of left another for right and one for content and a mix of overflow:hidden? Visual reference below;

[IMG][URL]http://i.imgur.com/HtuE2.png[/URL][/IMG]

I'll appreciate any help :downs:[/QUOTE]

The easiest way would be to just use an image as the background, but it should also be possible if you applied the blur to a smaller element behind the main body content.

[rzzi]

I can't seem to get data from a JSON object. Can someone help me and explain please? I'm still a noob with this stuff.

<html>
<head>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready( function() {
	$.getJSON("http://staff.tumblr.com/js/json?num=3&callback=?", function(data){
		$.each(data, function(i, tumblr_api_read) {
			var posts ="<li>";
			posts += '<a href="' + tumblr_api_read.tumblelog.posts[i].url '">' + tumblr_api_read.tumblelog.posts[i].url + "</a>";
			posts += "</li>";
			$("#posts").append(posts);
		});
	});
});
</script>
<head>
<body>
<ul id="posts"></ul>
</body>
</html>

[KmartSqrl]

[QUOTE=Richy19;30946512]So how can you provide the ajax functionality for users that dont have js[/QUOTE]

You realize that AJAX stands for Asynchronous [b]Javascript[/b] And XML right?

[Jelly_]

[QUOTE=Richy19;30946512]So how can you provide the ajax functionality for users that dont have js[/QUOTE]

Why wouldn't someone have javascript enabled?

[TehWhale]

[QUOTE=Jelly;30956700]Why wouldn't someone have javascript enabled?[/QUOTE]your kind using noscript

[Jelly_]

[QUOTE=TehWhale;30956711]your kind using noscript[/QUOTE]

Anyone with the technical know how to use noscript would know the downsides to using so, either they enable it or use a dysfunctional website.

[deadeye5362]

[QUOTE=R1Z3;30955739]I can't seem to get data from a JSON object. Can someone help me and explain please? I'm still a noob with this stuff.

$(document).ready( function() {
    $.getJSON("http://staff.tumblr.com/js/json?num=3&callback=?", function(data){
        $.each(data, function(i, tumblr_api_read) {
            var posts ="<li>";
            posts += '<a href="' + tumblr_api_read.tumblelog.posts[i].url [highlight]+[/highlight] '">' + tumblr_api_read.tumblelog.posts[i].url + "</a>";
            // Forgot a + right...........................................^
            posts += "</li>";
            $("#posts").append(posts);
        });
    });
});

[/QUOTE]

That should work, you forgot a + to concatenate the strings. I pointed it out in the posted code.

[rzzi]

[QUOTE=deadeye5362;30958362]That should work, you forgot a + to concatenate the strings. I pointed it out in the posted code.[/QUOTE]

I added the + but it still doesn't seem to run.

[editline]7th July 2011[/editline]

Debugged it and this came up:

[IMG]http://i52.tinypic.com/121ybrq.png[/IMG]

[deadeye5362]

[QUOTE=R1Z3;30960921]I added the + but it still doesn't seem to run.

[editline]7th July 2011[/editline]

Debugged it and this came up:

[IMG]http://i52.tinypic.com/121ybrq.png[/IMG][/QUOTE]

This means that tumblr_api_read.tumblelog is undefined. Make sure you're understanding the usage of $.each(). The function parameters used within $.each() are in the from of key, value (PHP's foreach style).

The way you're going about this looks more like 'for (var i in obj)'.

[Robber]

I'm working on a web application that has to be able to play sound files and skip ahead and back, pause/resume, etc. The soundfiles have the PCM S16 LE (araw) codec (at least that's what VLC tells me). I have absolutely no idea what player I could use. HTML5 audio doesn't support skipping and probably doesn't support the codec either and I've never used Flash in my whole life. Are there any free players I could use and can control from Javascript? It would be optimal if they were invisible.

[bbang]

[QUOTE=StinkyJoe;30952815]With my method you use $_SERVER['REQUEST_URI'] to get the original request uri, you have to work with that.[/QUOTE]

awesome, it works thanks.

[editline]7th July 2011[/editline]

I'm not sure how to describe this.. but anyways!

I have a code with array

$code = array('something','something1','something2','something3');

then i have foreach

	foreach ($code as $scrap => $code1) {
		if (!($code1 == $somethingelseoverhere)){
			echo'THIS IS SUPPOSE TO SHOW ONCE';
		} else {
			echo'Ok';
		}
	}

How do i make it show only once when the 2 variables aren't equal to each other?

[editline]7th July 2011[/editline]

Automerge doesn't work after 30min ? whoaaaaa

[editline]7th July 2011[/editline]

uhm, nevermind.

[editline]7th July 2011[/editline]

instead of arguing on WAYWO, help?

[editline]7th July 2011[/editline]

[SUB]T[/SUB]h[SUP]i[/SUP]s [SUB]p[/SUB]o[SUP]s[/SUP]t [SUB]i[/SUB]s [SUP]g[/SUP]o[SUB]i[/SUB]n[SUP]g[/SUP] [SUB]u[/SUB]p [SUP]a[/SUP]n[SUB]d[/SUB] [SUP]d[/SUP]o[SUB]w[/SUB]n

[deadeye5362]

$somethingdone = false;
$code = array('something','something1','something2','something3');
foreach ($code as $scrap => $code1) {    if (!($code1 == $somethingelseoverhere)){        echo'THIS IS SUPPOSE TO SHOW ONCE';    } else {
        echo $somethingdone ? 'Ok' : '';
        $somethingdone = true;    }}

Perhaps?

[rzzi]

Is there a place where I can learn simple PHP script for sessions/logins? Most tutorials are outdated because they show how to use session_register().

[compwhizii]

[QUOTE=R1Z3;30970500]Is there a place where I can learn simple PHP script for sessions/logins? Most tutorials are outdated because they show how to use session_register().[/QUOTE]

[url]http://net.tutsplus.com/tutorials/php/user-membership-with-php/[/url]

Look harder

[bbang]

Ok, so i have this code right here.
I the problem here is that when I get a wrong URL depending on the amount of 'pages' in the array, it will show '404' that much times.

Ex. It will show 2 times if you get it wrong using this.

[php=24,25,26,27,28,29,30,31,32,33,34]<?php
if ($_SERVER['REQUEST_URI'] == '/testmore/' || $_SERVER['REQUEST_URI'] == '/testmore/home') {
$_SERVER['REQUEST_URI'] = '/testmore/index';
}

echo $_SERVER['REQUEST_URI'];
echo '<br>';

$page = $_SERVER['REQUEST_URI'];

function dostuff($pagesC) {
echo 'yes!<br>';
echo $pagesC.'<br>';
}

$directory = '/testmore/'; //If you are in a directory! else leave it blank

$pagesB = array('index','mhm');

foreach ($pagesB as $scrap => $pagesC) {
if (!($directory.$pagesC == $page)){
echo '404<br>';
} else {
switch ($page) {
case $directory.$pagesC:
dostuff($pagesC);
break;
}
}
}
?>

[deadeye5362]

$pageArray = Array('index', 'mhm');

$directory = '/testmore/'; // Directory if in one. Otherwise, leave it as '/'.

$uriArray = explode('/', strstr($_SERVER['REQUEST_URI'], $directory, '' ));

if (in_array($uriArray[0], $pageArray)) {
    dostuff($uriArray[0]);
} else {
    echo '404';
}

No no need to loop.

[DaMoggen]

Damn, i'm so fucking bad with SQL.