Execute function on client?

[Super_Sonic]

I want a function to be called on all clients aswell as the server when i do a concommand, how would i do that?

This is what i have so far:

function test()
	//this is only called on the server i want it to also be client or something similar
end
concommand.Add("test_command", test)

[Overv]

[lua]for _, v in pairs( player.GetAll( ) ) do
v:ConCommand( "hai" )
end
RunConsoleComand( "hai" )[/lua]

[Super_Sonic]

[QUOTE=Overv;16816278][lua]for _, v in pairs( player.GetAll( ) ) do
v:ConCommand( "hai" )
end
RunConsoleComand( "hai" )[/lua][/QUOTE]

I tried something similar to that earlier and it says something like "ConCommand Blocked!" in the console

if SERVER then
function ctest()
        print("ranhere")
    end
    concommand.Add("ctest", ctest)
end

function test()
	for k,v in pairs(player.GetAll()) do
		v:ConCommand("ctest")
	end
end
concommand.Add("test_console", test)

[Overv]

Then do:

[lua]BroadcastLua( "LocalPlayer( ):ConCommand( \"ctest\" )" )[/lua]

[Super_Sonic]

That doesnt seem to work, i tried it and it calls the ctest() function but it still isnt client side(it doesnt print("ranhere2") in the console)

if SERVER then
function ctest()
        print("ranhere")
		if CLIENT then
			print("ranhere2")
		end
end
concommand.Add("ctest", ctest)
end

function test()
	BroadcastLua( "LocalPlayer( ):ConCommand( \"ctest\" )" )  
end
concommand.Add("test_console", test)

[Salads]

Why not just call the function directly since it's a global?

[lua]
BroadcastLua( "ctest( )" )
[/lua]

[ninjerss]

Instead of suggesting that the guy essentially use SendLua that he should actually learn the proper way of doing it and use a umsg that when hooked on the client, runs his code.

[MakeR]

What is wrong with using SendLua or BroadcastLua ninjerss?

[Super_Sonic]

Ok that works perfectly, thx for your help.

[Unrealomega]

[QUOTE=ninjerss;16817912]Instead of suggesting that the guy essentially use SendLua that he should actually learn the proper way of doing it and use a umsg that when hooked on the client, runs his code.[/QUOTE]

The only time it's a really problem is when the user has the opportunity to inject their own code. Seeing as they do not in this situation, it should be fine.

[LauIsFun]

[QUOTE=Unrealomega;16833259]The only time it's a really problem is when the user has the opportunity to inject their own code. Seeing as they do not in this situation, it should be fine.[/QUOTE]
we can inject before sendlua, and we can even block sendlua, besides that, this is the code that should be used instead of sendlua spam.

SERVER

local function RunTest()
--shit u wanna do
NWRunTest()
end

umsg.PoolString("RunTest")
function NWRunTest()
umsg.Start("RunTest",0)
umsg.End()
end

CLIENT

local function RunTest()
--shit u wanna do
end
usermessage.Hook("RunTest",function (um)
RunTest()
end)

[|FlapJack|]

[QUOTE=LauIsFun;16837335]we can inject before sendlua, and we can even block sendlua, besides that, this is the code that should be used instead of sendlua spam.

SERVER

local function RunTest()
--shit u wanna do
NWRunTest()
end

umsg.PoolString("RunTest")
function NWRunTest()
umsg.Start("RunTest",0)
umsg.End()
end

CLIENT

local function RunTest()
--shit u wanna do
end
usermessage.Hook("RunTest",function (um)
RunTest()
end)

[/QUOTE]

You called the function on the server before declaring it.

[LauIsFun]

[QUOTE=|FlapJack|;16839859]You called the function on the server before declaring it.[/QUOTE]
I didn't call it yet. it's in the function chunk, durp