Freeze function help

[sintwins]

Ok, when the function "stuck" is called will the player freeze? I know this is probably a total mess and is useless, but I'm just practising things :) thanks. Basically will the "player.freeze" work and if not how do I get it to work?

function stuck(length)
player.freeze(1)
for time=1,length do
msg("you're stuck for"..time.."seconds")
end
player.freeze(0)
end

[CombineGuru]

no

[sintwins]

[QUOTE=CombineGuru;19467232]no[/QUOTE]

Thanks. Very helpful. I now know what I have done wrong :)

[charozoid]

First, there are no function called stuck... Second, use the lua tage: [lua] [/lua] Third, this will maybe help you:

[lua]function FreezePly( ply )
for _, ply in ipairs( player.GetAll() ) do
player:Freeze( true )
end
timer.Simple( 5, player:Freeze( false )
conCommand( "ply_freeze", FreezePly )[/lua]

When you will enter ply_freeze in console, it will freeze all the player, then after 5 seconds, will unfreeze them.

UNTESTED!

[sintwins]

ok thanks.

[disseminate]

Your lua is fairly weird. for time = 1, length do will just print it length times all at once. player.Freeze takes a boolean as an argument.

[editline]02:14PM[/editline]

[QUOTE=bilbasio;19467511]First, there are no function called stuck... Second, use the lua tage: [lua] [/lua] Third, this will maybe help you:

[lua]function FreezePly( ply )
for _, ply in ipairs( player.GetAll() ) do
player:Freeze( true )
end
timer.Simple( 5, player:Freeze( false )
conCommand( "ply_freeze", FreezePly )[/lua]

When you will enter ply_freeze in console, it will freeze all the player, then after 5 seconds, will unfreeze them.

UNTESTED![/QUOTE]

This won't work either. The following will:

[lua]function FreezePly( ply )
ply:Freeze( true )
timer.Simple( 5, player.Freeze, false )
end
concommand.Add( "ply_freeze", FreezePly )[/lua]

[charozoid]

Thank you for correcting my error, its actually the first time I help someone :)

[disseminate]

You tried.

[Nev]

[QUOTE=Disseminate;19468412]Your lua is fairly weird. for time = 1, length do will just print it length times all at once. player.Freeze takes a boolean as an argument.

[editline]02:14PM[/editline]

This won't work either. The following will:

[lua]function FreezePly( ply )
ply:Freeze( true )
timer.Simple( 5, player.Freeze, false )
end
concommand.Add( "ply_freeze", FreezePly )[/lua][/QUOTE]

Nope, that won't work, too. However, this will:

[lua]function FreezePly( ply )
ply:Freeze( true )
timer.Simple( 5, ply.Freeze, ply, false )
end
concommand.Add( "ply_freeze", FreezePly )[/lua]

[charozoid]

[QUOTE=Disseminate;19469343]You tried.[/QUOTE]

Thats what i like to hear from people... You dont come here and do your good coder... Anyway I rated you polite