Calling a function within an array from within a sub array OF that array.

[DaneSomdahl]

local ShittyScript =
{
	Functions = {
		["Negro"] = function( a )
			print("[Negro]: " .. a);
		end
	},
	
	SeperateShit = {
		["DoThatNegro"] = function()
			--ShittyScript.Functions["Negro"]("Oh shit nigga you be doin me!")
		end
	}
}

The problem is:

I can do seperately [b]ShittyScript.Functions["Negro"]("Lylz")[/b], and it will print "[Negro]: Lylz" in console,
but I can't figure out how to call a function from WITHIN an array to the array that it's within.

MainArray ->
{
	FirstSubArray ->
	{
		Function1()
	}
		
	SecondSubArray ->
	{
		Function2()
		{
			Call Function1()
		}
	}
}

[Freze]

Say we use this:

[lua]MainArray =
{
FirstSubArray = {
["func1"] = function(arg) print(arg); end;
},
SecondSubArray =
{
["secondfunc"] = function() MainArray.FirstSubArray.func1("hi"); end;
},
}

MainArray.SecondSubArray.secondfunc()

> "hi"[/lua]

Fixed it.
And that above works.

[DaneSomdahl]

I've already tried that, it returns a nil value.

[lua\Blackpeople.lua:89] attempt to index global 'ArrayNegro' (a nil value)
B

[Freze]

I've just tested it. And it works
What's the full code?

[DaneSomdahl]

You tested that exact code? Because that exact has errors, could you copy over your exact block that works for you?

[Freze]

I did.

[lua]
MainArray =
{
FirstSubArray = {
["func1"] = function(arg) print(arg); end;
},
SecondSubArray =
{
["secondfunc"] = function() MainArray.FirstSubArray.func1("hi"); end;
},
}

MainArray.SecondSubArray.secondfunc()
[/lua]
That exact code works.

[editline]3rd March 2012[/editline]

[img]http://puu.sh/jhCH[/img]

[DaneSomdahl]

Oh okay thanks, I figured out my problem.

Apparently if

local MainArray = {

is localized, you can't call or get anything within it from inside of it.

[Freze]

Oh, yes. I forgot to mention about that. Sorry.

[DaneSomdahl]

It's okay, thanks!