Getting forward coord based on angle

[bobthe2lol]

If i have something's current coord position, and its angle in digrees, how can i get a position that is say 1 unit exactly in front of the current one based on it's angle? Thanks guys :P

[noctune9]

2D or 3D?

[bobthe2lol]

2D

[noctune9]

y = sin(angle*pi/180)+y_origin
x = cos(angle*pi/180)+x_origin

[bobthe2lol]

Oh great, thanks!

And to advance it more than 1 unit it just multiply that right?

[noctune9]

[QUOTE=bobthe2lol;22583544]Oh great, thanks!

And to advance it more than 1 unit it just multiply that right?[/QUOTE]

Yeah, like this:
y = sin(angle*pi/180)*length+y_origin
x = cos(angle*pi/180)*length+x_origin

[bobthe2lol]

Also, if i have a 2 coordinate positions, and the angle of one of them, how can i get how much that angle needs to turn so that the second one is directly in front of it?

[ZeekyHBomb]

Coordinates do not have an angle.

You are probably searching for the arctangent tough:
turnangle = atan2(y2 - y1, x2 - x1) - currentangle

Brush up a bit on your trigonometry :P

[nos217]

Am I right in saying that arctan is the same as tan^-1? Here in Britain we just call it inverse tan.

[ZeekyHBomb]

tan^-1 is just another way to write it. I find it weird though, since tan^-1(x) is not (tan(x))^-1, whereas tan^2(x) for example is (tan(x))^2.
The arc stands for arcus and means inverse I think.)

[bobthe2lol]

Yeah my trig sucks lol. Thanks Zeeky