C++ Reading the line below

[Axarator]

I have created a program that you search all the users that have ever used the program, but you need to enter your details to search. It is all fine and not buggy, but I have one thing I would like to know how to do. I would like to know so that when it searches it will enter everything on the line the string was found and the line below.

inFile.open("data.txt");
    cout << "\n";
    cin.get(entr); //dont worry about this. this is just something you don't need to know about.
    cout << "\nYou may now search a user\n";
    cout << "\nEnter a students first or last name ((Case sensitive))\n";
    getline (cin, search);
    cout << "\n Searching for " << search <<"\n";
	{
    size_t pos;
while(inFile.good())
  {
      getline(inFile,line); // get line from file
      pos=line.find(search); // search
      if(pos!=string::npos) // string::npos is returned if string is not found
        {
            cout << search << " Found!"; //this is where I want it to display the line the string was found and the line below, because the line below has the age.
            break;
        }
  }

[Protocol7]

You already have code that handles when the string was found, and you've already got an object for the line. You can write [I]line[/I] to your output to get the entire current line, call another [I]getline(inFile,line);[/I] (you may want to check if infile is still good, just to be safe), and then output [I]line [/I]again.

[Enternode]

In a completely unrelated question, is there a reason you're using the newline char rather than std::endl?

You're using the standard output library already, but I wanted to know if I am missing anything.

[Zeh Matt]

[QUOTE=TeamEnternode;48267512]In a completely unrelated question, is there a reason you're using the newline char rather than std::endl?

You're using the standard output library already, but I wanted to know if I am missing anything.[/QUOTE]

std::endl also flushes the buffer which isn't always needed really.