the problem states:
If f(2)=6, and f is one-to-one, find x satisfying 8 + f^-1(x-1) = 10
Is the first part irrelevant or does it have to be worked into the equation?
Because if its just finding x with only the equation than I can figure it out.
Also working it out would help me understand.
This deals with inverse functions.
This is a bonus problem because we haven't gone over it indepth yet, but I want to figure out how to do it.
Thank you :)
yes
The answer is X=99999999999999999999999999999999999999
8 + f^-1(x-1) = 10
f^-1(x-1) = 2
if f(2) = 6 then f^-1(6) = 2
x - 1 = 6
x = 7
if that's wrong then im going to feel really stupid
[QUOTE=No_0ne;37596124]8 + f^-1(x-1) = 10
f^-1(x-1) = 2
if f(2) = 6 then f^-1(6) = 2
x - 1 = 6
x = 7
if that's wrong then im going to feel really stupid[/QUOTE]
As some one who sucks at math.
What.
[QUOTE=No_0ne;37596124]8 + f^-1(x-1) = 10
f^-1(x-1) = 2
if f(2) = 6 then f^-1(6) = 2
x - 1 = 6
x = 7
if that's wrong then im going to feel really stupid[/QUOTE]
MR KNOWITALL
do it yourself bro
facepunch is not your personal calculator
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