A 6500 kg helicopter accelerates upward at 0.60 m/s^2 while lifting a 1200 kg car. The car is suspended beneath the helicopter by a steel cable. What is the lift force exerted on the air by the helicopter's rotor? (Hint: this will be the upward applied force acting on the helicopter.)
You add the mass of the car and helicopter, right?
m = 1200 + 6500 (?)
a = 0.6
Then there's the gravitational pull/weight of the helicopter and car g = 7700 x 9.81 (?)
Then you add 0.6 and 7700 x 9.81 to find the upward applied force acting on the helicopter?
And that's it?
Crap.. or is it just netforce=ma
[highlight](User was banned for this post ("Schoolpunch" - Jaanus))[/highlight]
>9,000
protip: do not ask facepunch to do your homework
[QUOTE=dcalde78;25467600]protip: do not ask facepunch to do your homework[/QUOTE]
I'm just asking someone to check my work :saddowns:
and I got good help last time.. unlike this time.
Hopefully Dude902 and swno1 who have been watching this thread for a while are going to assist me.
Um, 42.
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