[url]http://www.wolframalpha.com/input/?i=%281%2F0.64%29^%282%2Bx%29%3D1.543^%28x%2B1%29[/url]
If someone could show me the working, I am stuck on this part of the calculation:
[URL]http://www.wolframalpha.com/input/?i=2%28log%281%2F0.64%29%29-%28log%281.543%29%29%3D%28log%281.543%29x%29-%28log%281%2F0.64%29%29x[/URL]
Thanks!
I came here with the intention of chucking it into Wolfram Alpha.
OP ninja'd me...
[QUOTE=Terminutter;28030761]I came here with the intention of chucking it into Wolfram Alpha.
OP ninja'd me...[/QUOTE]
Its very handy for checking :) Just wish it could go into detail about how it works the answer out, I did find a equation solver site that could do show the working but it was pretty much illegible.
Ahh, I generally use it for checking if I got my answers correct, but I've not covered logarithms yet - just started AS level maths.
Seperate the exponentials into
Z^2 . Z^x = Y^x . Y^1
Divide Z^x by Y`x, the same for the other member of the equation.
Transform the x part into (Z/Y)^X
Use log to remove the x, and transform logZ/Y into log10, which I can't remember how to do right now.
That ought'a do it.
