• Anyone here remembers Calculus? I need help with a problem.
    3 replies, posted
Hey Guys! So I'm taking a refresher course to Calculus since I haven't took it in years, and I'm doing a problem where I'm supposed to find a expression that gives the slope of the secant line. I know how the slope form is and all, but for some reason it doesn't feel right. The F(x) is -16t^2 + 32t+128 with a point P(1,144), and a point G(t,h(t)) I wanted to make sure that I'm getting the correct expression. Here's the expression that I have obtained [QUOTE] h(t) = -16t[SUP]2[/SUP]+32t+128 Slope of the secant line = f(t)-(1)/t-1 [/QUOTE] Hopefully I did it correctly.
The slope of a secant line between those points is (F(x2) - F(x1)) / (x2 - x1) = h(t) - 144 / t - 1 so yes [editline]1st October 2014[/editline] you don't really need the formula, just two points
Alright! Thank you, Sir. I'm just making sure because the way the teacher worded it was weird. She worded it as [quote]Find an expression which gives the slope of the secant line which passes through the point P and a general point G(t,h(t)). [B]Simplify your answer[/B]<-- this what got me at first [/quote]
Sorry, I made a typo, the top half is h(t) - 144. Since the y coordinate of P is 144.
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