Write each polynomial as the product of two binomials.
I need somebody to explain to me how to do this, step by step, not just do it for me.
-3(x - 9) + x(x - 9)
Online help is currently offline -_-
[highlight](User was banned for this post ("School" - SteveUK))[/highlight]
Don't ask facepunch.
[editline]11:29AM[/editline]
Ask your teacher or a friend or an adult like a neighbor or someone.
[url]http://www.wolframalpha.com/[/url]
Ask the super computers you can use for free
Nope. And yeah, Wolfram Alpha can help a lot.
I have nobody else to ask ATM. And if i wait till tomorrow to ask my teacher, I'll get an F on the assignment.
Sent you a PM
I would help but I suck at explaining things; I just know how to solve the problem.
-snippo-
misread the OP
[url]http://wolframalpha.com[/url]
Type in an equation, it will solve, graph, etc it for you.
[editline]11:38AM[/editline]
[url=http://www.wolframalpha.com/input/pdfGet.jsp?id=MSP859199e7ce9hg1ah1070000221ig2bhe335d3ee&s=17&i=-3(x+-+9)+%2B+x(x+-+9)]Here's the answer, thank WolframAlpha.[/url]
Can't use calculators, I have a TI-84 Plus Silver >.>
NickFury, thats actually the most helpful response I got, I'm just stuck at factoring.
Here's a method to help you factor a polynomial in ax²+bx+c=0 format:
(x+2)(x-4)
This is the answer we want.
x²-2x-8
This is what we're starting with.
Okay.
1. Take the value of the variable [B]c.[/B] c=-8 in this case.
2. Next, analyze the different factors of the c variable's [B]absolute value.[/B] It's important you use a positive number, here's why:
8:
1 x 8
2 x 4
3. Now, use trial and error to determine, when adding each factor, which of those combinations will give you the correct value for the variable [B]b[/B]. This is where you take into consideration the fact that the value of the c variable is negative.
Our b value is -2.
1 x 8 --Neither of these, no matter which is negative, will give us a sum of -2.
2 x 4 --Therefore, it has to be this combination.
2 + 4 = 6
-2 + 4 = 2
2 - 4 = -2 --Bingo.
Place these factors into your binomial answer format.
(x ) (x )
2 -4
Your answer is indeed:
(x+2)(x-4)
and you're done!
I'm in advanced calculus, this is something that has to be engraved in our heads every day of our lives. :3:
If you need help with this stuff you'll be dying in calculus.
^^ Agree so much.
[url]http://www.wolframalpha.com/input/?i=what+is+-3(x+-+9)+%2B+x(x+-+9[/url])
Cool, I haven't used Wolfram Alpha since it launched.
For solving equations in the form of ax^2 + bx + c = 0 and if you have a calculator, you can use these equations. They'll give you both answers if you can't be bothered working it out yourself:
(-b+sqrt(B^2 - 4ac))/2a
(-b-sqrt(B^2 - 4ac))/2a
They look stupid on here but they're actually quite simple.
[url]http://www.mathway.com/[/url]
[QUOTE=Encryption;20473893]Can't use calculators, I have a TI-84 Plus Silver >.>
NickFury, thats actually the most helpful response I got, I'm just stuck at factoring.[/QUOTE]
dude what the fuck, that is seriously the best TI out there, why can't you do something that simple with it? You don't even need a fucking calculator.
Factoring stupified:
Find 2 numbers that add up to b and whose product is c.
Follow this:
ax^2+bx+c=0
So say the first number is d and the second number is e.
So you would end up with (x+d)(x+e)=0
To be able to get 0 with 2 factors, at least one has to equal 0.
So yadda yadda...
x+d=0
x=-d
and
x+e=0
x=-e
Unless it can be proven wrong, both answers would be correct.
Sarah Palin said that
Also seriously I learned this is 6th grade what the fuck?
[editline]06:06PM[/editline]
Automerge is broken. :saddowns:
[editline]06:08PM[/editline]
[QUOTE=Sarah Palin;20475446]dude what the fuck, that is seriously the best TI out there, why can't you do something that simple with it? You don't even need a fucking calculator.[/QUOTE]
I have the same one but I can't bother to figure out its controls. I would do the math faster on paper than if I input all the numbers into the calculator anyway.
[QUOTE=Jund;20475489]Also seriously I learned this is 6th grade what the fuck?
[editline]06:06PM[/editline]
Automerge is broken. :saddowns:
[editline]06:08PM[/editline]
I have the same one but I can't bother to figure out its controls. I would do the math faster on paper than if I input all the numbers into the calculator anyway.[/QUOTE]
algebra 2 in 6th grade? not possible unless your teachers are really dumb.
[QUOTE=Sarah Palin;20475446]dude what the fuck, that is seriously the best TI out there, why can't you do something that simple with it? You don't even need a fucking calculator.[/QUOTE]
We aren't aloud to use a fucking calculator...
[QUOTE=Encryption;20473618]Write each polynomial as the product of two binomials.
I need somebody to explain to me how to do this, step by step, not just do it for me.
-3(x - 9) + x(x - 9)
Online help is currently offline -_-[/QUOTE]
(-3 + x)(x - 9)
lol this isn't algebra 2, its pre-algebra
you can't hide from us 13 year olds
[QUOTE=Beardy;20475865]algebra 2 in 6th grade? not possible unless your teachers are really dumb.[/QUOTE]
Or maybe [i]your[/i] teachers are really dumb, I learned pre-algebra at the end of 6th grade.
Wow, you're 11 or something, this stuff is old for me.
Man i regret that message, such a weak 2.500th post.
[QUOTE=Encryption;20473618]Write each polynomial as the product of two binomials.
I need somebody to explain to me how to do this, step by step, not just do it for me.
-3(x - 9) + x(x - 9)
Online help is currently offline -_-[/QUOTE]
It's really simple actually. Take -3(x - 9), you multiply whatever's in the brackets by what's outside. So -3*x is -3x and -3*-9 is 27. There's your first one and then you do the second one, x*x is x^2 (to the power of) and x*-9 is -9x. Then you simplify it to be x^2 - 12x + 27. Correct me if I'm wrong.
Ninja'd about 50 times...
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