[img]http://img715.imageshack.us/img715/5193/firstx.png[/img]
So when
[img]http://img825.imageshack.us/img825/6500/second.png[/img]
(and a is a real number)
[img]http://img693.imageshack.us/img693/6130/thirdd.png[/img]
[img]http://img843.imageshack.us/img843/1254/fourthu.png[/img]
Therefore a = -a when a > 0. What am I doing wrong?
I wish I was good at math, I have no clue what anything here means.
Good job sir
I think all my teachers just ripped me off.
The square root of a number is +/- the square root of that number.
You can't know if the square root is negative or positive because if you square either one you'll get the same answer.
[QUOTE=ThePuska;24257128][img]http://img715.imageshack.us/img715/5193/firstx.png[/img]
So when
[img]http://img825.imageshack.us/img825/6500/second.png[/img]
(and a is a real number)
[img]http://img693.imageshack.us/img693/6130/thirdd.png[/img]
[img]http://img843.imageshack.us/img843/1254/fourthu.png[/img]
Therefore a = -a when a > 0. What am I doing wrong?[/QUOTE]
:what: Eehh what the hell?
[img]http://img265.imageshack.us/img265/4333/mahts.jpg[/img]
I think this is your problem.
But but but
Sqrt(x*x) =/= Sqrt x * Sqrt x/
[editline]07:00AM[/editline]
GODDAMN NINJA D:
l
Or maybe not. It's been years since I did algaebra
[QUOTE=TH89;24257226]Or maybe not. It's been years since I did algaebra[/QUOTE]
I have my calcoolator right here. What you said was right.
Just used it to test, :v:
Yeah, it does seem that the former always results in |x| and the latter in x. But sqrt(ab) = sqrt(a)sqrt(b) is true in most cases - at least with positive a and b.
If you have, for example, sqrt(4x), you can say it's equal to sqrt(4)sqrt(x) and therefore 2sqrt(x)
[QUOTE=TH89;24257213][IMG]http://img265.imageshack.us/img265/4333/mahts.jpg[/IMG]
I think this is your problem.[/QUOTE]
Pretty much this.
Consider this
Sq of 1 = 1 x=1
1x1=1, sq of 1=1
BUT you can't take the sqroot of a negative number, math just doesn't work that way.
the median is a
:downs:
Hold up I'm confused.
Gonna have to think on this a bit :v
[QUOTE=TH89;24257213][img]http://img265.imageshack.us/img265/4333/mahts.jpg[/img]
I think this is your problem.[/QUOTE]
It's correct.
Suppose x=2
Square root of 4 (2*2) is 2.
= = =
Square root of 2 * square root 2 = 2.
Umm It is obvious when dealing with square roots that the square can be positive or negative
2 * 2 = -2 * -2 = 4
However this does not mean that 2 = -2 due being false logic.
However you screwed up in that X^2 does not translate to -A^2 as -A^2 = a^2. Even if you do screw that up somehow. you still turned the square root of -a^2 into the square root of -1 and A ^2 if anything it would be -1 * the square root of a^2.
And you missed the simple trick of squaring something cancels out the getting the square root.
I thing you need to go through your math books again.
Fuck i was in this thread when it was full of derp and now it isn't...
[QUOTE=kevn150;24257312]It's correct.
Suppose x=2
Square root of 4 (2*2) is 2.
= = =
Square root of 2 * square root 2 = 2.[/QUOTE]
Not if X is a negative number.
Squrate root of (-2x-2)
THat comes out as 2
you can't take the square root of -2 by itself
[QUOTE=TH89;24257213][img]http://img265.imageshack.us/img265/4333/mahts.jpg[/img]
I think this is your problem.[/QUOTE]
It's right.
[QUOTE=Cypher_09;24257344]It's right.[/QUOTE]
Not when dealing with negative numbers.
My username does not fit me as I do not know how to calculate this.
Fuck you summer and your forgetfulness-inducing ways.
I like how you guys try to argue about basic algebra.
Are you guys trying to make a black hole or what?
[QUOTE=TH89;24257226]Or maybe not. It's been years since I did algaebra[/QUOTE]
Why are you a moderator again :geno:
Uhg, here.
When you take the SQUARE ROOT of a negative number, you get I.
IxI= -1 (don't ask me why)
So the square root of (-2) x the square root of (-2) = -2
however
The square root of (2) x the square root of (2) = 2
[QUOTE=TH89;24257213][img]http://img265.imageshack.us/img265/4333/mahts.jpg[/img]
I think this is your problem.[/QUOTE]
root(16) = 4
root(4) * root(4) = 4
Oh how I miss algebra.
[QUOTE=Neolk;24257362]Not when dealing with negative numbers.[/QUOTE]
You can't have the sqrt of a negative number.
[QUOTE=TrafficMan;24257396]root(16) = 4
root(4) * root(4) = 4[/QUOTE]
Once again, take into account negative numbers.
SERIOUSLY, TRY THAT WITH NEGATIVE NUMBERS.
We would all save time if we realized being in debt one dollar is not the same as owning a dollar.
[QUOTE=Neolk;24257424]Your math is awful.[/QUOTE]
Good lord, I just realized how stupid that was. 2AM after a round of Team Fortress 2 does not help my thinking at all.
[QUOTE=Neolk;24257412]Once again, take into account negative numbers.
SERIOUSLY, TRY THAT WITH NEGATIVE NUMBERS.[/QUOTE]
You don't do SqRt with negatives unless you get into imaginary (i) numbers which tend to just fuck everything up.
They also, if I remember right, don't equal 0.
[QUOTE=Cypher_09;24257403]You can't have the sqrt of a negative number.[/QUOTE]
It becomes I, an imaginary number.
Because you can't get a "square root" of it, it proves that he fucked up with the root(x*x) = root(x) * root(x)
[editline]02:16AM[/editline]
[QUOTE=Doom14;24257416]This.
SqRt of 4 x 4 = 16
SqRt of 4 x SqRt of 4 = 4
(2 x 2 = 4)[/QUOTE]
Your math is awful.
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