Ohms Equation:
U = IxR ....
U = 16V
I = ??
R = ?? ....
Can somebody tell me how to canculate this ??
I am trying to do this ...
[IMG]http://desmond.imageshack.us/Himg853/scaled.php?server=853&filename=breznaslovaa.png&res=medium[/IMG]
I would measure it but I do not have the proper device. Thanks for any helps.
THIS IS NOT HOMEWORK!
[highlight](User was banned for this post ("Yes it is, and this is your second homework thread/UTT" - Starpluck))[/highlight]
If I * R = 16 and you don't know neither I nor R you can't solve it.
Assuming the ammeters have 0 resistance, the resistance of the parallell part of the circuit is 1/R = 1/600 + 1/300, then add the extra 300 from the resistor in series to all of that.
So R is [1/(1/300)+(1/600)] + 300 = 500 (though I don't know what units the resistances are given in the image)
ammeter have 0 resistance yes.... But 1/R1,2,3 = 1/R1,2 + 1/R3 = ?? ...
and It all have to be set to 16V ....
Sorry, you need to Log In to post a reply to this thread.