SetModelScale and GetModelScale

[LocoJoker]

Hello
I'm fairly new to Lua and trying to improve my knowledge by fixing up broken gamemode and learning new functions and I've hit a brick wall

[Lua]
function META:Grow()
for _,ply in pairs(player.GetAll()) do
if self:GetPos():Distance(ply:GetPos()) < 200 then
if ply.Stank == nil then
ply.Stank = {Level = 1,}
else
ply.Stank.Level = ply.Stank.Level + 1
end
timer.Simple(math.random(10,30),function() if ply:IsValid() then ply:EmitScent() end end )
end
end
if self:GetModelScale().x < 10 then
self:SetModelScale(self:GetModelScale() + Vector(.05,.05,.05))
timer.Simple(math.random(10,30),function() if self:IsValid() then self:Grow() end end )
end
end
[/Lua]

Now I believe ive fixed the SetModelScale issue by putting this in the initial cl_init

[Lua]
function Entity:SetModelScale(scale)
local mat = Matrix()
mat:Scale(scale)
self:EnableMatrix("RenderMultiply", mat)
end
[/Lua]

But GetModelScale from what I've read now works completely different as well
Any help would be appreciated
Thanks Guys

[DevulTj]

What are you asking us to do?

[Donkie]

Probably just want to do like
[lua]
function Entity:SetModelScale(scale)
self.fModelScale = scale
blablabla
end
function Entity:GetModelScale()
return self.fModelScale or 1
end
[/lua]

[LocoJoker]

I was trying to find a replacement for GetModeScale.

And Donkie that worked perfectly thanks! :D

Mind explaining to me what that did? as I said I'm doing this to learn.

[Feihc]

The arguments for SetModelScale have been changed. It no longer takes a vector, it takes two floats (I believe)
SetModelScale(float Scale, float TimeToSize)

The first float is what you wish to scale to (2 for 2x as large, .5 for 1/2 as large) and TimeToSize is the time it takes for the model to reach that size.

Pros: Easier to use
Cons: Cannot scale as easily on an individual axis

Unsure about GetModelScale

[SweetTea]

[QUOTE=mib999;39157277]What are you asking us to do?[/QUOTE]

please stop shitposting everywhere, you dont know lua anyways.