Java: How to tell an if statement to ignore multiple values without writing them all out? (grouping?

[djjkxbox360]

I want to do an if statement but I need to write this for example "if (variable != 24 && != 36 && != 54..." and continuing on with a lot more. However I don't want a huge line of code. Is there anyway to group these numbers so I can write "if (variable != groupednumbers)"

Thanks in advance

[Map in a box]

Use an array and arrays.contains

[Contron]

I suppose you could have an ArrayList of Integers and simply call

if (myList.contains(someNumber))
{
     //something
}

Of course, there's probably a better method.

[editline]14th March 2012[/editline]

Ninja'd

[Smashmaster]

If it's a really huge list and they're all sorted like your example you could do a binary search.

[Map in a box]

Yeah just call Arrays.sort after you store everything in the array.

[Smashmaster]

Got bored and just wrote the code for you.

    private static final int[] list = new int[]{24, 36, 56, 64, 75, 101, 205, 543, 939, 1024, 1292, 4834, 9593, 10020};
    
    public static void main(String[] args)
    {
        System.out.println(contains(64));
    }
    
    private static boolean contains(int n)
    {
        int a = -1;
        int b = list.length;
        while (true)
        {
            int i = (a + b) / 2;
            int ni = list[i];
            if (n > ni) a = i;
            else if (n < ni) b = i;
            else return true;
            if (Math.abs(a-b) <= 1) return false;
        }
    }

[Asheron]

[QUOTE=Smashmaster;35140936]Got bored and just wrote the code for you.

    private static final int[] list = new int[]{24, 36, 56, 64, 75, 101, 205, 543, 939, 1024, 1292, 4834, 9593, 10020};
    
    public static void main(String[] args)
    {
        System.out.println(contains(64));
    }
    
    private static boolean contains(int n)
    {
        int a = -1;
        int b = list.length;
        while (true)
        {
            int i = (a + b) / 2;
            int ni = list[i];
            if (n > ni) a = i;
            else if (n < ni) b = i;
            else return true;
            if (Math.abs(a-b) <= 1) return false;
        }
    }

[/QUOTE]

You don't even have to bother doing that, there is a binarySearch method in the Arrays class.

[url]http://docs.oracle.com/javase/1.4.2/docs/api/java/util/Arrays.html[/url]