Lets play a game

[sertan]

So lets play a game. Who can debug this code? It is in Javascript. Have fun.

/**
* #################################################################
# ALFAVA METRAXIS #
# #
# #
# #
# YOUR NAME #
# #
# #
# #
# PHONE NUMBER EMAIL ADDRESS #
# #
# #
#################################################################

# This program works out the cost of new business cards for the user.
# The base cost of the cards is £2 for 50. However users can customise their cards at additional cost
*/

//This line allows us to use command line input and output
var io = require('./io');

// Creating a variable to hold the total cost of their order in £

// Print an introduction out to the user
io.output("Welcome to Alfava Metraxis (TM). This program will help you design your perfect business card.");

// Before we print out this line we'll add a newline for prettiness
io.output("You get the first 8 characters free. After that it is 10p per character for the next 10 characters and 2p per character thereafter");

// Their name goes across the middle of the card. We'll ask them for it and store it in a variable
var theirName;
theirName = io.input("What is your name? ");

// We'll confirm their name as it's so important

if(io.input("Is your name ", theirName + "?") == "yes")
{
// They entered their name wrong and we need to change it. Good job we checked!
theirName = io.input("What is your name? ");
}

/*
* The card cost goes up based on the length of their name. Your £2 gets you 8 characters (excluding spaces).
* Thereafter it's 10p per character for the next 10 characters and 2p for every character thereafter.
*/

/* We need the length of their name to know how much to charge them */
var nameLength;
nameLength = theirName.length();

// Given that length, what's the cost
if(nameLength > 8 && nameLength < 18)
{
// Add 10p per character
totalCost += (nameLength - 8) * 10;
}
if(nameLength > 18)
{
// Add 2p per character
totalCost += (nameLength - 18) * 2;
}

// Let's inform the user of how much *extra* this is going to cost them. I've formatted it nicely as well
io.output("The length of your name is", length, "which will cost an additional £" + parseFloat(totalCost).toFixed(2));

//-----------------------------------------//

/*
# On their card they can have an email address AND/OR a phone number.
# They get only one of these included the basic cost.
# If they want both it costs another £1.
# If they want neither they can save 50p
*/

// Ask if they want an email address on their card
var emailWanted = io.input("Do you want an email address? ", theirName + "?");

if(emailWanted)
{
// If they do then ask them what it should be
var emailAddress = io.input("What is your email address? ", theirName + "?");

}

// Ask if they want an phone number on their card
var phoneNumberWanted = io.input("Do you want a phone number? ", theirName + "?");

if(phoneNumberWanted)
{
// If they do then ask them what it should be
phoneNumber = io.input("What is your phone number? ", theirName + "?")
}

// Add £1 to the total cost if they want both
if(phoneNumberWanted && emailWanted);
{
totalCost += 1;

// Take 50p off if they don't want either
if(!phoneNumberWanted || !emailWanted)
{
totalCost -= 0.5;
}
}

/*
# They can also have the corners of their cards curved (at extra cost of course)
# If they want an even number curved then they pay an additional £3 divided by the number of curves
# If they want an odd number curved then they pay an additional £5 divided by the number of curves
# This does mean that if they want more curves it costs less - it's just a quirk of the manufacturing process!
*/

// Find out how many corners they would like curved
var numberOfCurves = io.input("How many curved corners would you like? ", theirName + "?");

// This line tells us whether we have an even number of curves or an odd one.
if(numberOfCurves % 2 == 1)
{
// Even number - add on cost
totalCost += 3 / numberOfCurves;
}
else
{
// Odd number - add on cost
totalCost += 5 / numberOfCurves
}

//-----------------------------------------//

/*
We are currently running a deal for them - they can order both shiny and matte cards and we'll give them
the lower number of cards for free
*/

// How many orders do they need?
io.output("\nYou can order both shiny and matte cards and we'll give you the lower number free of charge")

var smallerNumber = parseInt(io.input("How many shiny cards would you like? ", theirName + "?"));
var biggerNumber = parseInt(io.input("How many matte cards would you like? ", theirName + "?"));

// If they want more shiny cards then just swap these round
if (biggerNumber < smallerNumber)
{
smallerNumber = biggerNumber;
biggerNumber = smallerNumber;
}

// Let them know how many free cards they're getting!
io.output("You will get", smallerNumber, "free copies! Bargain eh!\n");

//-----------------------------------------//

//***************************************************//
//The order is now complete - let's summarise what we're giving them
//***************************************************//
io.output("Your order summary\n-----------");
io.output("The name is:", theirName);
if(phoneNumberWanted)
{
io.output("The phone number is", phoneNumber);
}
if(emailWanted)
{
io.output("The email address is", emailWanted);
}
io.output("Number of curved corners is", numberOfCurves);

/*
* We need some way to contact them
* They may have given us a phone number or an email address already, wo let's use that.
* But if they've not given us either, OR they've given us both we'll have to ask
* */

if(phoneNumberWanted)
{
if(emailWanted)
{
//Both email and phone number around - ask them which one
contactDetails = io.input("Give me a phone number or email address to contact you on ", theirName + "?");
}
if(!emailWanted)
{
if (!phoneNumberWanted)
{
// No email and no phone number - let's ask
contactDetails = io.input("Give me a phone number or email address to contact you on ", theirName + "?");
}
else if (phoneNumberWanted)
{
// We have no email but we do have a phone
contactDetails = phoneNumber;
}
}}
else if(!phoneNumberWanted)
{
if (emailWanted)
{
// No phone but do have email
contactDetails = emailAddress;
}
else
{
// no email and no phone - ask
contactDetails = io.input("Give me a phone number or email address to contact you on ", theirName + "?");
}
}
else
{
// Don't have anything - just ask them
contactDetails = io.input("Give me a phone number or email address to contact you on ", theirName + "?");
}

io.output("OK, your order has gone through and we will contact you on", contactDetails);

io.output("Goodbye");

[Naarkie]

no

[sertan]

It's alright now I think I am getting through it lol