Easiest way to pass a filename to a function?

[Tricky D]

I'm using C++ for this.

Right now I have a function that plays a sound

e.g. I call it like this

PlaySound();

then in the PlaySound function it's something like

LoadWav("../sounds/sound.wav");
PlayWav;

I want to change it I can do this

PlaySound(filename);

then in the function

LoadWav(filename);
PlayWav;

What is the easiest way to do this?

[DarkCybo7]

.... Use function parameters?

Is this question super trivial or am I just not understanding it.

[StylixX]

Just use a const char* or std::string as a parameter?

[Tricky D]

[QUOTE=Robbis_1;40236177]Just use a const char* or std::string as a parameter?[/QUOTE]

wow, I feel so stupid

i think this is a case of it's so easy that I couldn't see it, thank you

[G4MB!T]

[QUOTE=o DefcoN o;40236207]i think this is a case of it's so easy that I couldn't see it[/QUOTE]

i dont think so...

[DoctorSalt]

I think you're thinking of file names as their own object (opposed to it being a string). Understandable, but now you know.

[Relaxation]

Pass it from main as argv[] if youre using commandline, then in the function itself do the whole fopen() business. This is what id do for testing purposes in early stages.

[DarkCybo7]

[QUOTE=Relaxation;40258720]Pass it from main as argv[] if youre using commandline, then in the function itself do the whole fopen() business. This is what id do for testing purposes in early stages.[/QUOTE]

what the hell

[Relaxation]

-snip- posted while intoxicated

[dajoh]

[QUOTE=Relaxation;40258810]lmao, just saw he said c++, not c!!

but yes, if he wanted to pass a filename from the commandline to the function that opens and plays it, the prototype would look like void playSound(char **file)

and in the main function you would call it like playSound(argv[1]);
e.g. the command line innvocation is ./program soundfile

But thats how i would TEST it in C, due to preferences / tools.

as someone already told the op, filename is just a string.[/QUOTE]

what the fucking hell

[DarkCybo7]

[QUOTE=Relaxation;40258810]lmao, just saw he said c++, not c!!

but yes, if he wanted to pass a filename from the commandline to the function that opens and plays it, the prototype would look like void playSound(char **file)

and in the main function you would call it like playSound(argv[1]);
e.g. the command line innvocation is ./program soundfile

But thats how i would TEST it in C, due to preferences / tools.

as someone already told the op, filename is just a string.[/QUOTE]

argv[1] is a char *

also i don't know how to making this a commandline argument has anything to do with what he's talking about

[cucumber]

You have to use TCHAR, also use double slashes, not one backslash in C++ when pathing to file.
it will be something like this:

TCHAR fileName[MAX_PATH];
fileName = L"C:\\Users\\Desktop\\music.wav";
LoadWav(TCHAR);

PlayWav(filename);

[Dienes]

[QUOTE=cucumber;40570728]You have to use TCHAR, also use double slashes, not one backslash in C++ when pathing to file.
it will be something like this:

TCHAR fileName[MAX_PATH];
fileName = L"C:\\Users\\Desktop\\music.wav";
LoadWav(TCHAR);

PlayWav(filename);[/QUOTE]

TCHAR is non-standard and Windows only. Just use wchar_t if you are required to have Unicode support (which you are not in this example but OP might be depending on his locale and folder names)

[Ollie]

[QUOTE=cucumber;40570728]You have to use TCHAR, also use double slashes, not one backslash in C++ when pathing to file.
it will be something like this:

TCHAR fileName[MAX_PATH];
fileName = L"C:\\Users\\Desktop\\music.wav";
LoadWav(TCHAR);

PlayWav(filename);[/QUOTE]

You are trying to LoadWav() a variable type?
Shouldn't it be LoadWav(fileName);

Also don't use TCHAR if you really don't have to.