A cyclist maintains a constant velocity of 5.3 m/s headed away from point A. At some [B]initial time[/B], the cyclist is 254 m from point A. What will be his displacement from his starting position after 41s?Answer in units of m.
The fuck does initial time mean. What the fuck does it even want from me.
It wants to steal your bike so it can catch up.
-snip-
[editline]04:19PM[/editline]
It means he is currently 254 meters away from point A I believe. So figure out how far he will go in meters in 41 seconds at 5.3 meters per second, Add that to 254 and there you have it.
He cycled for 48 seconds.
48s - 7s = 41 seconds
5.3m/s x 7 = 37.1m
254m - 37.1m = 216.9m
Answer:
216.9m in 41 seconds.
I think that's it, dunno
Apparently the answer is 217.3m
:confused:
[QUOTE=Valdor;24720239]Apparently the answer is 217.3m
:confused:[/QUOTE]
-snip-
:words:
I didn't read the question right
[QUOTE=Valdor;24720239]Apparently the answer is 217.3m
:confused:[/QUOTE]
But see he started at 254 meters so add that onto that and I believe THAT is your answer.
[editline]04:36PM[/editline]
[QUOTE=badMedia;24720210]He cycled for 48 seconds.
48s - 7s = 41 seconds
5.3m/s x 7 = 37.1m
254m - 37.1m = 216.9m
Answer:
216.9m in 41 seconds.
I think that's it, dunno[/QUOTE]
Where are you pulling the 7 from?
[QUOTE=slashsnemesis;24720367]But see he started at 254 meters so add that onto that and I believe THAT is your answer.[/QUOTE]
Hmm I might be wrong because I didn't read the question right :fuckyou:
Really all that is needed is a simple formula
Distance = (Rate)(Time)
D = (5.3)(41)
D = 217.3 meters
Add that to 254 and that should be your answer.
[quote=slashsnemesis;24720367]but see he started at 254 meters so add that onto that and i believe that is your answer.
[editline]04:36pm[/editline]
where are you pulling the 7 from?[/quote]
meh I read the question wrong
shameless bump for physics lesson
Initial time means nothing. That's like me saying "After some time, I'm X/y away from A." If it said "After X seconds" then it would be a completely different case. BUT, I won't go there.
So, the cyclist is cycling at 5.3 m/s. That means every second. he is traversing [B]five and one third[/B] meters of ground. All you know is that he goes that fast in one second, and that after some amount of time he reaches a distance of 254 meters from his initial starting place.
The "254 meters" is 100% useless. The question is asking you how far he will be after 41 seconds of traveling at his constant velocity of 5.3 m/s [I]from his starting position. [/I]As in, from point A. The 254 m is just there to throw you off.
D=vt
D=(5.3)(41)
D=217.3
:science:
[editline]10:57PM[/editline]
In the real world you would have to compensate for acceleration, hence why I said it would be different if it gave you "after X seconds."
My head hurts :psyduck:
This is 1st grade math compared to what I'm being taught now. And what I'm being taught now feels like 1st grade math. And soon what I'll be taught next will be like 1st grade math.
Physics is ridiculously easy once you open your mind a bit and think a little less harder about things.
[editline]11:00PM[/editline]
I could show you vectors.
Wow are you all seriously this horrible at math
If you wanted to find the time it took him to go from point A to 254 meters, use t = d/v.
t = (254)/(5.3)
t = 47.92 seconds
Once you get the formulas down it's as easy as plugging stuff into a calculator and using a function or two.
Say the journey was 50 meters, the problem is only concerned about the last 41 meters, and the time at which he reached that distance is the initial time.
[quote]
[CICº]Muffykins: e.g. Timmy starts at 0 m/s and then starts cycling. After 10 seconds he reaches a constant velocity of 3.5 m/s and then slows down. At this initial time of 15 seconds he is only going at a rate of 2.1 m/s.
Fumples: OH FUCK
[CICº]Muffykins: How much did Timmy accelerate in the first 10 seconds of cycling?
[CICº]Muffykins: When he slowed down?
[CICº]Muffykins: How far did Timmy travel all together?
Fumples: At the initial time of five seconds, Tyrone happened to be walking by and managed to take it.
[/quote]
I can't tell if it wants the distance from point A after 41 seconds or the distance from the point 254m from point A. The question isn't too clear on that.
The answer is either 217.3m or 471.3m depending on which it is.
[editline]12:24AM[/editline]
I guess it's 217.3 but that makes half the info you're given completely extraneous.
The OP said the answer was 217.3 a few posts up.
Also the answer to my question quoted in my last post.
[quote]a = deltaV/time
a (first 10 seconds) = .35 m/s
Rate of acceleration in first 10 seconds: .35 seconds
When Timmy slowed down, he was at 15 seconds. That means in a span of 5 seconds he went from 3.5 m/s to 2.1 m/s. SO, this is where a = deltaV/time comes in.
A = (2.1-3.5)/(5)
A = -0.28 m/s
Yes, you can have negative acceleration.
As for the last bit, "How far did Timmy travel all together?" just multiply 3.5 by 10 and add that to 2.1 times 5, you get total distance.
D = ((3.5)(10)+(2.1)(5))
D = (35)+(10.5)
D = 45.5m
Full answer would look like this
How much did Timmy accelerate in his first 10 seconds?
Timmy accelerated at 0.35 m/s in his first 10 seconds of cycling.
When he slowed down?
When Timmy slowed down -0.28 m/s was taken from his total acceleration of 3.5 m/s for a total of five seconds.
How far did Timmy travel all together?
Timmy traveled a total distance of 45.5 meters.
Seriously this shit is easy.[/quote]
god dammit i love physics and math
[QUOTE=haloguy234;24770870]
Also the answer to my question quoted in my last post.
god dammit i love physics and math[/QUOTE]
Cool story bro.
Make a thread about it.
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