Its really a simple question, but I'm getting stuck on it.
I simply have N2 + 3H2 -> 2NH3. There are five liters of nitrogen gas. What volume of ammonia is produced?
Now, using ideal gas law and STP the answer, I think, is 20 liters of NH3, but can someone work it out for me?
The way I originally did it was 5 liters N2 * (1 mol N2 / 22.4 L N2) * (2 mol NH3 / 1 mol N2) * (22.4 L NH3 / 1 mol NH3) = 10L. Which isn't right? But all my other stoichiometry problems worked the same way for mass-mass stuff. It would be kind of silly if for volume the formula all of a sudden changed and I had to know both reactants to get the product, though it is possible/easy.
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