• Need help with Algebra 2 homework.
    55 replies, posted
I remember doing this in Grade 7/8. =/
[QUOTE=Beardy;20476687][quote=synth](-3 + x)(x - 9)[/quote]no it's (x - 3)(x - 9)[/QUOTE] You're both right! :derp:
The funny thing is, we do this shit a lot and we're in 11th year top set math. I think our teacher is trying to fuck with us or something.
[QUOTE=ProgramFiles;20476939]Wow, you're 11 or something, this stuff is old for me. Man i regret that message, such a weak 2.500th post.[/QUOTE] I'm actually in Liberal Arts (Between Geometry and Algebra 2) We do Algebra 2 content at a shit slow pace.
what?, I could do this, and I'm in algebra 1
Can anybody show me how to factor? =)
Hmm, what do you want to factorise?
I learned off some chick on facebook.
Oh, okay :v:
-3(x - 9) + x(x - 9) You take (x - 9) out as the common factor (It's a straightforward translation from mah language). You get (x - 9)(-3*1 + x*1) = (x - 9)(x - 3)
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are u leik rtarded or smth =? [img]http://img192.imageshack.us/img192/5323/87292040.jpg[/img]
I always factored by grouping. But I still have problems sometimes with factoring.
[QUOTE=Epic Sandwich;20475065]For solving equations in the form of ax^2 + bx + c = 0 and if you have a calculator, you can use these equations. They'll give you both answers if you can't be bothered working it out yourself: (-b+sqrt(B^2 + 4ac))/2a (-b-sqrt(B^2 + 4ac))/2a They look stupid on here but they're actually quite simple.[/QUOTE] What no The determinant is -b^2[B]-[/B]4ac (notice the minus)
[QUOTE=i_speel_good;20477659]What no The [b]determinant [/b]is -b^2[B]-[/B]4ac (notice the minus)[/QUOTE] You mean the discriminant :eng101: and it's b^2-4ac
Sorry my bad, thought it looked a bit strange.
Can i ask how old you are? We were doing this stuff age 14.
The fuck, I do this when I was in algebra 1... Lucky bastard :(
I graduated high school and I don't even know how to do that.
[QUOTE=Bledrix;20478798]I graduated high school and I don't even know how to do that.[/QUOTE] You have substandard intelligence. Sorry.
[QUOTE=Encryption;20473618]Write each polynomial as the product of two binomials. I need somebody to explain to me how to do this, step by step, not just do it for me. -3(x - 9) + x(x - 9) Online help is currently offline -_-[/QUOTE] This is Algebra 2? I remember doing distributive property in 8th grade.
Um... Notice how there are two (x - 9)? Just take their coefficients and "undistribute" them: (-3 + x)(x - 9) or (x - 3)(x - 9)
[QUOTE=Equidistratic;20479325]This is Algebra 2? I remember doing distributive property in 8th grade.[/QUOTE] algerbra 2 is just a review for the first two months
Shit, that's Algebra 2? Fuck man that's low-level algebra. [editline]09:30PM[/editline] [QUOTE=Sh33p;20479089]You have substandard intelligence. Sorry.[/QUOTE] Hahah, you still think educated is the same thing as intelligent.
[QUOTE=Jund;20476899]Or maybe [i]your[/i] teachers are really dumb, I learned pre-algebra at the end of 6th grade.[/QUOTE] uhhh you do know that it goes from general math > pre-algebra > algebra 1 > geometry > algebra 2??? which means he's saying he started pre-algebra in 3rd grade.
I never took pre-algebra in the first place skipped it
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