• The Theory of Infinite Distance.
    244 replies, posted
[QUOTE='[LOA] SonofBrim;17348164']Why so many dumb ratings? This really got me thinking of how we, when we are approaching something, constantly get closer performing an infinite loop, yet somehow reach our goal. WOW O_O[/QUOTE] Because that infinite loop is less than a finite number.
[QUOTE='[LOA] SonofBrim;17348164']we, when we are approaching something, constantly get closer performing an infinite loop, yet somehow reach our goal. WOW O_O[/QUOTE] Um, what?
It's because when x=0, y=0, but they don't draw the line. 1/0 is infinite, correct? however, the sqrt of 1 is both +1 and - 1 due to the fact that (-1)(-1) and (1)(1) both equal 1. Also, 1/1 is 1 1/-1 is -1. However 0 is the average of -1 and 1. If you divided any number by zero, you would get both positive and negative infinite, if you average that out it'd be 0. This graph just proves it.
[QUOTE=Wayword;17348208]It's because when x=0, y=0, but they don't draw the line. 1/0 is infinite, correct? however, the sqrt of 1 is both +1 and - 1 due to the fact that (-1)(-1) and (1)(1) both equal 1. Also, 1/1 is 1 1/-1 is -1. However 0 is the average of -1 and 1. If you divided any number by zero, you would get both positive and negative infinite, if you average that out it'd be 0. This graph just proves it.[/QUOTE] 1/0 does not exist at all. the graph of 1/x approaches infinity as X approaches zero, it is a big difference.
[QUOTE=Valnar;17348244]1/0 does not exist at all. the graph of 1/x approaches infinity as X approaches zero, it is a big difference.[/QUOTE] 1/0 exsists but the answer is imaginary. You can't put no value into value; 1/x approaches infinity is not real, infinity on a graph should be represented on a limit, you cannot walk for infinity.
[QUOTE=Valnar;17348244]1/0 does not exist at all. the graph of 1/x approaches infinity as X approaches zero, it is a big difference.[/QUOTE] However, 1/-.0000001 is a very low number similarily, 1/.0000001 is a very high number. If you averaged them out you would get 0. We're dealing with imaginary numbers here.
[QUOTE=FFStudios;17348263]1/0 exsists but the answer is imaginary. You can't put no value into value; 1/x approaches infinity is not real, infinity on a graph should be represented on a limit, you cannot walk for infinity.[/QUOTE] It's not imaginary.
[QUOTE=FFStudios;17348263]1/0 exsists but the answer is imaginary. You can't put no value into value; 1/x approaches infinity is not real, infinity on a graph should be represented on a limit, you cannot walk for infinity.[/QUOTE] 1/0 is undefinied, and when I said 1/x approaches infinity I implied that as a limit. Imaginary numbers are what you get when you take the square root of a negative number.
[QUOTE=JohnnyMo1;17348278]It's not imaginary.[/QUOTE] It's not a real number you can put a value to however. [editline]11:17PM[/editline] [QUOTE=Valnar;17348280]1/0 is undefinied, and when I said 1/x approaches infinity I implied that as a limit.[/QUOTE] as x gets closer to 0, y gets closer to infinite. If x was 0, y would be infinite. What is hard to understand.
[QUOTE=Wayword;17348283]It's not a real number you can put a value to however. [editline]11:17PM[/editline] as x gets closer to 0, y gets closer to infinite. If x was 0, y would be infinite. What is hard to understand.[/QUOTE] Because you can't calculate 1/0, You are talking about lim(1/x) x->0 which can be calculated.
Division by zero, you can write it down 1/0, but you get not result at all. Is not imaginary, the result doesn't exist
[QUOTE=Valnar;17348299]Because you can't calculate 1/0, You are talking about lim(1/x) x->0 which can be calculated.[/QUOTE] It can't be calculated no. But if you graph it you would get the same conclusion as I did.
[QUOTE=Wayword;17348320]It can't be calculated no. But if you graph it you would get the same conclusion as I did.[/QUOTE] The graph never reaches infinity, it only approaches it.
[QUOTE=Valnar;17348336]The graph never reaches infinity, it only approaches it.[/QUOTE] What do the arrows on the lines mean? It goes on. Forever. As you said before it never reaches 0 but it approaches it. if x WERE to reach 0 however. If we assumed it could. Y would be infinite. However, since infinite has no set value, it's not a real number and it's just hypothetical concept.
[QUOTE=Wayword;17348364]What do the arrows on the lines mean? It goes on. Forever. As you said before it never reaches 0 but it approaches it. if x WERE to reach 0 however. If we assumed it could. Y would be infinite. However, since infinite has no set value, it's not a real number and it's just hypothetical concept.[/QUOTE] You can't assume you can do something that is impossible.
[QUOTE=Valnar;17348389]You can't assume you can do something that is impossible.[/QUOTE] Sure you can with theoretical data. Infinite is impossible, but so are a lot of things. Assumably if you could move faster than the speed of light, time would slow down and might even stop (depending on your source) However it'll never happen, since anything with a non-zero mass will never reach the speed of light. Didn't stop physicist from theorizing it. Except for that one particle that does move faster than photons, but lets forget about that for now.
[QUOTE=Wayword;17348414]Sure you can with theoretical data. Infinite is impossible, but so are a lot of things. Assumably if you could move faster than the speed of light, time would slow down and might even stop (depending on your source) However it'll never happen, since anything with a non-zero mass will never reach the speed of light. Didn't stop physicist from theorizing it. Except for that one particle that does move faster than photons, but lets forget about that for now.[/QUOTE] Look, what I am saying is that 1/0 is an undefinable answer, you are thinking of the limit of 1/0 which is infinity.
If you bounce bounce a ball, and each time it bounces back up it reaches 1/2 of of the origional height, and you measure that ball, you will never reach a specific number. Say you drop it from 1 foot, and then it goes to .5, and .25, and then .125 and then add it, it'll reach to 1 + .5 + .25 + .125 + .0625 + .03125 + 0.015625 = 1.984375 ect ect ect. Eventually the number will keep getting BIGGER, but 1.98 will never become 1.99 or 2. you'll get to something like .0000000000125 and then .0000000000000065, but its irrelevant. All it is is more decimals.
[QUOTE=Neolk;17348510]If you bounce bounce a ball, and each time it bounces back up it reaches 1/2 of of the origional height, and you measure that ball, you will never reach a specific number. Say you drop it from 1 foot, and then it goes to .5, and .25, and then .125 and then add it, it'll reach to 1 + .5 + .25 + .125 + .0625 + .03125 + 0.015625 = 1.984375 ect ect ect. Eventually the number will keep getting BIGGER, but 1.98 will never become 1.99 or 2. you'll get to something like .0000000000125 and then .0000000000000065, but its irrelevant. All it is is more decimals.[/QUOTE] If you round it, it's 2. DELTA BOUNCE = 1.9999999999999999999999999 FEET
[QUOTE=Neolk;17348510]If you bounce bounce a ball, and each time it bounces back up it reaches 1/2 of of the origional height, and you measure that ball, you will never reach a specific number. Say you drop it from 1 foot, and then it goes to .5, and .25, and then .125 and then add it, it'll reach to 1 + .5 + .25 + .125 + .0625 + .03125 + 0.015625 = 1.984375 ect ect ect. Eventually the number will keep getting BIGGER, but 1.98 will never become 1.99 or 2. you'll get to something like .0000000000125 and then .0000000000000065, but its irrelevant. All it is is more decimals.[/QUOTE] But as you divide the distance remaining into small and smaller intervals, you must divide the time taken to cross these distance intervals into smaller intervals as well. (I'm referring to the original problem, not the bouncing ball.)
*fap fap fap fap fap*
[QUOTE=sheyzok;17348545]*fap fap fap fap fap*[/QUOTE] I know baby, infinitesimals get me horny too.
[QUOTE=JohnnyMo1;17348568]I know baby, infinitesimals get me horny too.[/QUOTE] Along with H.P. Lovecraft? You make me sick.
[QUOTE=JohnnyMo1;17348544]But as you divide the distance remaining into small and smaller intervals, you must divide the time taken to cross these distance intervals into smaller intervals as well. (I'm referring to the original problem, not the bouncing ball.)[/QUOTE] B-B-But, I said that... Sort of.
Undefinable limits turn me on lim(infinity - infinity) lim(1^infinity) lim(infinity^infinity), yeah.
[QUOTE=Valnar;17348643]Undefinable limits turn me on lim(infinity - infinity) lim(1^infinity) lim(infinity^infinity), yeah.[/QUOTE] Oh god, lim x->∞ (1 + 1/x)^x, I love how equivalent you are to e
You know what else is hot? Electron orbital shapes. Oh 4f orbital, you really know how to treat a science nerd.
[QUOTE=Canuhearme?;17347893][img]http://grokrobots.com/wp-content/uploads/2008/04/science_robot.gif[/img][/QUOTE] Does that come on a t-shirt?
[QUOTE=JohnnyMo1;17348568]I know baby, infinitesimals get me horny too.[/QUOTE] oh newton... that hot son of a bitch...
Interesting.....
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