[QUOTE=Number-41;49850639]Don't think I wanna end up in "the industry" either, I imagine you have to work in big teams and make deadlines and adhere to a plan. I'll probably try to do a PhD so I can work individually and in a more "creative" way.
[Editline] 2th March[/Editline]
On the other hand $$$$$$$$$$$$[/QUOTE]
I am struggling to finish my practical math Bachelors, and I can't even go study another advanced degrees. meh
Why not?
[QUOTE=Number-41;49852857]What kind of physics? I had the impression you shifted more to pure maths :P[/QUOTE]
String theory, which is about as close to pure math as you can stay in physics! :v:
For instance [url=http://arxiv.org/abs/1512.08586]here's[/url] the most recent arXiv paper of the professor at my undergrad school that I most wanted to study with. Definitely manages to stay pretty abstract.
[QUOTE=JohnnyMo1;49855395]String theory, which is about as close to pure math as you can stay in physics! :v:
For instance [url=http://arxiv.org/abs/1512.08586]here's[/url] the most recent arXiv paper of the professor at my undergrad school that I most wanted to study with. Definitely manages to stay pretty abstract.[/QUOTE]
this is the stuff that makes me want to pursue a more substatial knowledge of pure mathematics
since there isn't a class on abstract algebra for undergrads, do you have any recommendations for a course that would at least get my feet wet, per se?
I'm trying to find the length of y = sqrt(x) - (1/3)x^(3/2) where 1<=x<=4
I know that it's equal to the integral of the square root of (1+y')
So I get the integral from 1 to 4 of sqrt(1 + (1-x)/(2*sqrt(x)))dx
Wolfram alpha keeps spitting out this enormous antiderivative with imaginary numbers
Where did I go wrong?
[QUOTE=cody8295;49860906]I'm trying to find the length of y = sqrt(x) - (1/3)x^(3/2) where 1<=x<=4
I know that it's equal to the integral of the square root of (1+y')
So I get the integral from 1 to 4 of sqrt(1 + (1-x)/(2*sqrt(x)))dx
Wolfram alpha keeps spitting out this enormous antiderivative with imaginary numbers
Where did I go wrong?[/QUOTE]
arc length is
[IMG]http://i.imgur.com/zU4DpJp.png[/IMG]
gotta square your derivative
[QUOTE=NixNax123;49860941]arc length is
[IMG]http://i.imgur.com/zU4DpJp.png[/IMG]
gotta square your derivative[/QUOTE]
Ah shit, thanks.
[QUOTE=Number-41;49853212]Why not?[/QUOTE]
I mean, after I finish this degree, I can't go study masters or PhD.
I heard if you do something extraordinary that doors are open though.
[QUOTE=NixNax123;49855706]this is the stuff that makes me want to pursue a more substatial knowledge of pure mathematics
since there isn't a class on abstract algebra for undergrads, do you have any recommendations for a course that would at least get my feet wet, per se?[/QUOTE]
Well if your university doesn't have abstract algebra for undergrads, I'd need to know what it does offer to recommend something.
[QUOTE=cody8295;49861046]Ah shit, thanks.[/QUOTE]
I'm still having problems finding the length of this function.
y = sqrt(x) - (1/3)x^(3/2) where 1<=x<=4
For y' I have (1-x)/(2*sqrt(x))
and for y'^2 I have (x^2-2x+1)/4x
But when I plug that into wolfram alpha it spits out some crazy half imaginary half real solution
Here's the exact query i'm typing in
[QUOTE]antiderivative of sqrt(1+(x^2 - 2x + 1)/4x) dx[/QUOTE]
Really would appreciate any help on this
[QUOTE=cody8295;49880542]I'm still having problems finding the length of this function.
y = sqrt(x) - (1/3)x^(3/2) where 1<=x<=4
For y' I have (1-x)/(2*sqrt(x))
and for y'^2 I have (x^2-2x+1)/4x
But when I plug that into wolfram alpha it spits out some crazy half imaginary half real solution
Here's the exact query i'm typing in
Really would appreciate any help on this[/QUOTE]
Hint: here's how you reduce your radicand:
[IMG]http://i.imgur.com/qwAjtrI.png[/IMG]
(and you're also giving wolframalpha wrong input)
I'm taking a Calculus 2 course, and I wasn't really expecting to like it because I heard a lot of bad things about it from other students, but I am actually loving it.
We're currently doing Infinite Series, and it's quite fun. A bit difficult at times, though, but I think I'll manage. :smile:
[QUOTE=NixNax123;49880746]Hint: here's how you reduce your radicand:
[IMG]http://i.imgur.com/qwAjtrI.png[/IMG]
(and you're also giving wolframalpha wrong input)[/QUOTE]
Why is my input wrong?
I was wondering if you guys could help me understand how to calculate this one thing.
How would I find out, without counting them one by one, how many numbers exists between 1000-9999 that has either the number 3 or 4 at least once? The problem seems to be under combinatorics.
[QUOTE=Trebgarta;49924681]Finally a question I have enough math knawledge to answer :P
So you say either or, in 4 digit numbers? Count no 3 or 4s, and subtract. Makes 7 * 8* 8* 8 = 3584. 8999 other numbers, so 5415 of em contain 3 or 4 in any position.[/QUOTE]
Thank you very much! Cleared up a lot, somehow didn't even think of using that methdod.
How would you guys solve x^x=2 ?
In Mathematica.
Pretty sure the Lambert W-function will pop up, so if you were expecting something nice you're gonna have a bad time.
x log (x) = log(2)
x = log(2)/log(x)
now just iterate until x_n converges:
x_i+1 = log(2)/log(x_i)
Dear god,
please forgive all my sin,
cos I need to pass the math exam on may 13th.
Thank you
chills
Nah calculus is pretty dope if you know what you are doing and have strong foundations. Except my foundations aren't up to standards :v:
I am taking topology this quarter coming up, so that is going to be fun. All of the homework is already online so I already took care of the first week's work and probably will be able to finish more of it before the week is done.
[QUOTE=doom1337;49987998]I am taking topology this quarter coming up, so that is going to be fun. All of the homework is already online so I already took care of the first week's work and probably will be able to finish more of it before the week is done.[/QUOTE]
Topology is dank.
Is there a lot of maths involved in intro to macroeconomics and microeconomics classes? Because i want to take those classes as complementary courses but I never done any math like calculus or linear algebra.
[QUOTE=ichiman94;49978804]Dear god, please forgive all my sin, cos I need to pass the math exam on may 13th. Thank you chills Nah calculus is pretty dope if you know what you are doing and have strong foundations. Except my foundations aren't up to standards :v:[/QUOTE]
I wish you the best of luck! :smile:
Right now I'm doing an independent study abstract algebra. For some reason I find it interesting.
I don't know how this stuff could possibly be useful.
Just found out like 5 minutes ago that its supposedly the stuff that :quotes:string theory:quotes: (lol) is made of.
I found the book I'm using at the community college I'm dual enrolled at and they gave it to me for free, Hillman & Alexanderson. Their loss I guess.
[QUOTE=Chaitin;49991818]Is there a lot of maths involved in intro to macroeconomics and microeconomics classes? Because i want to take those classes as complementary courses but I never done any math like calculus or linear algebra.[/QUOTE]
Intro-level classes? Mine didn't require any of that. Calculus might help but it's far from a necessity.
We were given the formula for price elasticity of demand between two points in my microecon class and I asked if you could find it at one point. My professor said he didn't think so. I took a limit, and then verified it on Wikipedia, so that's some indication of how not necessary calculus is.
[QUOTE=Demx;49993504]Right now I'm doing an independent study abstract algebra. For some reason I find it interesting.
I don't know how this stuff could possibly be useful.
[/QUOTE]
A bit related: [URL="http://math.stackexchange.com/questions/426325/evaluate-int-01-frac-log-left-1x2-sqrt3-right1x-mathrm-dx"]holy shit[/URL]
[Editline]23rd March[/Editline]
Brb browsing top-voted [integration] questions on maths SE.
[QUOTE=Demx;49993504]:quotes:string theory:quotes: (lol)[/QUOTE]
fite me
[URL=http://arxiv.org/abs/1404.1499]The best paper from 2014.[/URL]
[QUOTE=Demx;49993504]Right now I'm doing an independent study abstract algebra. For some reason I find it interesting.
I don't know how this stuff could possibly be useful.[/QUOTE]
Here's a neat way it's useful: Can you agree geometry is useful? Physicists and engineers have been using geometry practically for centuries. Algebraic geometry provides a neat link between abstract algebra and geometry. Basically it turns problems in certain "geometric spaces" (schemes) into corresponding problems in "algebraic spaces" (commutative rings). Categorically, this is because the category of affine schemes is dual to the category of commutative rings.
I can't math at all (hoping to change that over time) but thanks OP for introducing me to latex, best way to ditch microsoft office imo.
Also, is there a nice open alternative to matlab/mathematica?
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