I always wondered how the number 0 can exist if it equals to nothing. Similarly, infinity.
I'm making a 77 in algebra 2. :3
[QUOTE=Bulmer;17845228]I always wondered how the number 0 can exist if it equals to nothing. Similarly, infinity.[/QUOTE]
Both are concepts.
I think.
Does 7/22 = pi?
[QUOTE=TechSpeek;17845271]Does 7/22 = pi?[/QUOTE]
No. And it's 22/7, and it's an approximate value, like 3.14.
You have 12 coins and 3 bags.
Your task is to put the coins in the bags, but they can't contain an even ammount of coins.
[QUOTE=Flip pl;17845508]You have 12 coins and 3 bags.
Your task is to put the coins in the bags, but they can't contain an even ammount of coins.[/QUOTE]
Impossible. (Odd + Odd = Even)
(Even - Even = Even)
Therefore 12 - (Odd + Odd) will always be an even number. You can get 2/3 bags with odd numbers but the third will always have an even number of coins in it.
Just think harder.
Not in a conventional way.
[QUOTE=Flip pl;17845658]Just think harder.
Not in a conventional way.[/QUOTE]
Oh, I got it!
1 in one bag
11 in the other bag
0 in the last bag.
Therefore, no bags contain an even number of coins. Solved!
No, you are still wrong.
You HAVE to put at least one coin in each bag.
[QUOTE=Flip pl;17845686]No, you are still wrong.
You HAVE to put at least one coin in each bag.[/QUOTE]
argh fuck you :v:
Your wording says
[quote]put the coins in the bags[/quote]
which I did. The coins are in the bags.
[editline]07:00PM[/editline]
Alright. Does it involve putting bags inside bags?
One coin in one bag, 11 in the other. Put one of these bags inside the last?
If you insist:
[QUOTE=Flip pl;17845508]You have 12 coins and 3 bags.
Your task is to put the coins in the bags, but they can't contain an even ammount of coins [b]and you have to put at least one coin in each bag[/b].[/QUOTE]
[QUOTE=Rasrap Smurf;17845788]One coin in one bag, 11 in the other. Put one of these bags inside the last?[/QUOTE]
I think you got it
[QUOTE=Rasrap Smurf;17845788]One coin in one bag, 11 in the other. Put one of these bags inside the last?[/QUOTE]
Close.
[QUOTE=Flip pl;17845828]Close.[/QUOTE]
Shove all the coins up your ass and hope nobody notices.
[QUOTE=BaconDioxide;17845860]Shove all the coins up your ass and hope nobody notices.[/QUOTE]
Well I did notice, game over you cheater.
[QUOTE=Flip pl;17845884]Well I did notice, game over you cheater.[/QUOTE]
Damn. I was a fool to think you wouldn't notice coins being shoved up your ass.
One coin in bag A, two in bag B and nine in bag C, and put bag A in bag B?
[QUOTE=Rasrap Smurf;17845912]One coin in bag A, two in bag B and nine in bag C, and put bag A in bag B?[/QUOTE]
You got that right, have a cake:
[img]http://img.timeinc.net/recipes/i/recipes/sl/02/11/chocolate-cake-sl-366569-l.jpg[/img]
its real:
A 'snooker' table (measuring 8 metres by 4m) with 4 'pockets' (measuring 0.5m and placed at diagonal slants in all 4 corners) contains 10 balls (each with a diameter of 0.25m) placed at the following coords:
2m,1m...(white ball)
...and red balls...
1m,5m... 2m,5m... 3m,5m
1m,6m... 2m,6m... 3m,6m
1m,7m... 2m,7m... 3m,7m
The white ball is then shot at a particular angle from 0 to 360 degrees (0 being north, and going clockwise).
Just to make it clear, a ball is 'potted' if at least half of the ball is in area of the 'pocket'
Assuming the balls travel indefinitely (i.e. no loss of energy via friction, air resistance or collisions), answer the following:
a: What exact angle/s should you choose to ensure that all the balls are potted the quickest?
b: What is the minimum amount of contacts the balls can make with each other before they are all knocked in?
c: Same as b, except that each ball - just before it is knocked in - must not have hit the white ball on its previous contact (must be a red instead of course).
d: What proportion of angles will leave the white ball the last on the table to be potted?
[QUOTE=Egg_Toaster;17855095]4y-9+8y(7-3)+7y+1y
20y-60[B]=[/B]40
y=5
Tell me if this is wrong.[/QUOTE]
Where did that equal sign come from?
4y - 9 + 8y(7-3) + 7y + 1y =
4y - 9 + 56y - 24y + 7y + y =
4y - 9 + 40y =
44y - 9
what is pie divided by infinite of pi
You get a shit load of pie.
[QUOTE=plokoon9619;17856871]what is pie divided by infinite of pi[/QUOTE]
0
[QUOTE=OnDemand;17834276]1+3+3=7[/QUOTE]
:aaa:
Sorry, you need to Log In to post a reply to this thread.
