[QUOTE=JohnnyMo1;25672740]Breaking it into two one-dimensional equations is super unnecessary. You can just use the range equation relaxin posted.[/QUOTE]
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Doesn't come naturally for me. I use it really rarely.
[editline]27th October 2010[/editline]
Besides it's an extremely unintuitive formula. You either just remember it or look it up.
For Velocity
Sin(2@)=9.81*500/v
1=9.81*500/v
9.81*500/1=v
v=4905
For 14deg
Sin(2*14)=9.81*d/4905
Sin(2*14)*4905/9.81=234.73
For 76deg
Sin(2*76)=9.81*d/4905
Sin(2*76)*4905/9.81= 234.73
For 350m
Sin(2*X)=9.81*350/4905
9.81*350/4905=0.7
Sin(2*X)=0.7
arcsin0.7=X/2
44.43=x/2
44.43/2=x
x=22.215
[QUOTE=RELAXiN;25673268]For Velocity
Sin(2@)=9.81*500/v
1=9.81*500/v
9.81*500/1=v
v=4905
For 14deg
Sin(2*14)=9.81*d/4905
Sin(2*14)*4905/9.81=234.73
For 76deg
Sin(2*76)=9.81*d/4905
Sin(2*76)*4905/9.81= 234.73
For 350m
Sin(2*X)=9.81*350/4905
9.81*350/4905=0.7
Sin(2*X)=0.7
arcsin0.7=X/2
44.43=x/2
44.43/2=x
x=22.215[/QUOTE]
v^2 = 4905 m^2 / s^2
v is about 70 m/s
For 14 and 76 degrees the result distance looks correct
In the last calculation you should have
44.43 = x*2
x = 44.43/2
x = 22.215
I didn't check it thoroughly but at a glance those seemed to be wrong. And for the angle, notice that x0 = 22.215 degrees is only one of the solutions. The other significant solution would be x1 = 45 + 22.215.
Then you'd also have solutions like 22.215 + 360, 22.215 + 2*360 etc. but those probably don't matter in this case
[editline]27th October 2010[/editline]
You forgot to square the v there but it kind of balanced itself out in the distance calculations because you forgot it consistently
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