[LUA] Position isn't accepting even tough it's correct?

Garry's Mod coding
#1

So first lemme give you da code



for k,spawnLocation in pairs(spawns) do
	ply:PrintMessage( HUD_PRINTTALK, "Checking every spawn position in data... Current positon: " .. tostring(spawnLocation) )
	if spawnLocation == br_spawn:GetPos() then
		ply:PrintMessage( HUD_PRINTTALK, "Found exact position in data! Removing..." )
		spawns[k] = nil
		br_spawn:Remove()
		ply:PrintMessage( HUD_PRINTTALK, "Spawnpoint removed." )
		break
	else
		ply:PrintMessage( HUD_PRINTTALK, "Wrong position..." )
	end
end

And the problem is when comparing position of the “br_spawn” with “spawnLocation” it just doesn’t let through, the code underneath isn’t ran. And the message “Wrong position…” is shown…



ply:PrintMessage( HUD_PRINTTALK, "Wrong position..." )





if spawnLocation == br_spawn:GetPos() then

Why is that happening?

Thanks.

#2

That means br_spawn’s positions match none of the spawn locations.

#3

That I know well I don’t know because when I edit something and undo It’ll work. But when I reload it won’t I am confused.

#4

Are you storing the spawns to a file or something? Reloading the game resets the Lua state so tables will be cleared.

#5

I am using my friend’s JSON wrapper. If I think how it works is that it’ll convert a table into a json table and then save it.

EDIT: I am not restarting the game but changing map.

#6

Changing the map is the same. Print out the table once you’ve loaded to make sure the JSON was parsed correctly.

#7

It is loading correctly as I am printing the value of it here:



ply:PrintMessage( HUD_PRINTTALK, "Checking every spawn position in data... Current positon: " .. tostring(spawnLocation) )

and the position is a normal vector.

#8

The only way it would not pass is if br_spawn’s pos doesn’t match any of the vectors. Print out all the vectors and br_spawn’s in the beginning to check.

#9 


Spawn position: -1131.970215 928.084961 1543.539307
Checked position: -1131.970215 928.085022 1543.539307





.084961
.085022

:excited:

#10

Alternatively, you can use this method if you want to check if the vectors are “equal” within a margin of error:

Vector:IsEqualTol

#11

You can use Vector1:Distance(Vector2) <= r (where r = 5 for example)

#12

Vector:IsEqualTol is a cheaper way to achieve the same thing, and it’s more readable, and it saves a square-root operation.

#13

Vector:Distance calculates the distance using the square root function, unnecessary when you are only using the result as a threshhold. If you really want to go down the road of checking it that way, use

Vector:DistToSqr, however code_gs’ solution is the correct one.

[editline]1st August 2017[/editline]

I spent so long writing that post due to distractions that I got ninja’d by a whole 15 minutes.

#14

Can I ask how to use that? I mean I don’t know what to put at the second argument.

#15

[lua]
if ( spawnLocation:IsEqualTol( br_spawn:GetPos(), 0.5 ) ) then
– Found exact point in data stuff
else
– other stuff
[/lua]

#16

I mean what is the second argument? Like the maximum vector can be different than this vector?

#17

Vector:IsEqualTol
next time look it up by yourself please.

#18

Dude… I searched it and didn’t knew what it meant. Or I didn’t knew what the word meant…

#19

It’s tolerance. It means that it will accept values in a range of ± the second arg.

#20

Thanks.