What is wrong with this code?

Garry's Mod coding
#1

Simple question, what is wrong with this code?

[lua]function ENT:Grow()
ent:SetPos(ent.GetPos + Vector(0,0,5) )
end

timer.Create( “Atimer”, 5, 1, ENT:Grow )[/lua]

It just keeps giving me “Expected arguments at ,”

#2

I believe it should be
[lua]timer.Create( “Atimer”, 5, 1, ENT.Grow, ENT )[/lua]

#3

have you tried creating the timer like
[lua]
function ENT:Initialize()
timer.Create(“GrowTime”, 5, 1, self:Grow)
end
[/lua]

#4

That’s right because these two are the same:

[lua]
Ent:Grow()
–same as
Ent.Grow(Ent)
[/lua]

The : is just a short way of doing it. The first argument is hidden and called self to the function it belongs to.

#5 

timer.Create( "Atimer", 5, 1, function() 	
ent:SetPos(ent.GetPos + Vector(0,0,5) )
	end
end

No?

#6

[lua]
function ENT:Initialize()
timer.Create(“Atimer”, 5, 1, self.Grow)
end

function ENT:Grow()
self:SetPos(self:GetPos() + Vector(0, 0, 5))
end
[/lua]

That should work.

#7

[lua]
function ENT:Initialize()
timer.Create( “Atimer”, 5, 1, self.Grow, self )
end

function ENT:Grow()
self:SetPos(self:GetPos() + Vector(0,0,5) )
end
[/lua]

#8

Ohh, I forgot about it. Thanks Ralle for correction.

#9

It worked to a degree, but I want the timer to start again when it’s finished, which it did when it was not in the ENT:Initialize() but I can’t take it out if ENT:Initialize() because it will make it impossible to get the self variable if you get what I mean.

#10

The 1 in the timer function tells it how many times to run, change it to 0 and it will never stop.